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洛谷

BZOJ

线段树维护,每个节点上面记录66个值l0,l1,r0,r1,m0,m1l0,l1,r0,r1,m0,m1(套路),代表从左开始最长00的序列长度,最长11的序列的长度,从右开始的…,中间的…(懒)

翻转就是把他们两两交换,pushup\rm pushup也都是套路。

注意覆盖标记比翻转标记优先级高,于是区间覆盖的时候会把翻转标记设成00pushdown\rm pushdown的时候也是先判断区间覆盖标记。

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#include <bits/stdc++.h>
#define MAXN 100005
using namespace std;
inline int read(){
int x=0,f=1;
char ch=getchar();
while (ch<'0'||ch>'9'){
if (ch=='-') f=-1;
ch=getchar();
}
while (ch>='0'&&ch<='9'){
x=(x<<3)+(x<<1)+(ch^'0');
ch=getchar();
}
return x*f;
}
int a[MAXN];
namespace SegmentTree{
struct node{
int l,r;
int l0,r0,l1,r1,m0,m1;
int sum,tag;
bool rev;
inline int len(){return r-l+1;}
}tree[MAXN<<2];
#define lc i<<1
#define rc i<<1|1
inline void Rev(int i){
tree[i].sum=tree[i].len()-tree[i].sum;
swap(tree[i].l0,tree[i].l1);
swap(tree[i].r0,tree[i].r1);
swap(tree[i].m0,tree[i].m1);
tree[i].rev^=1;
}
inline void Cover(int i,int val){
tree[i].tag=val;
tree[i].sum=val*tree[i].len();
tree[i].l0=tree[i].r0=tree[i].m0=(1-val)*tree[i].len();
tree[i].r1=tree[i].l1=tree[i].m1=val*tree[i].len();
tree[i].rev=0;
}
inline void pushdown(int i){
if (tree[i].l==tree[i].r) return ;
if (tree[i].tag!=-1){
Cover(lc,tree[i].tag),Cover(rc,tree[i].tag);
tree[i].tag=-1;
}
if (tree[i].rev){
Rev(lc),Rev(rc);
tree[i].rev=0;
}
}
node operator + (node a,node b){
node c;
c.l=a.l,c.r=b.r;
c.l0=a.l0;
if (a.sum==0) c.l0=max(c.l0,a.len()+b.l0);
c.l1=a.l1;
if (a.sum==a.len()) c.l1=max(c.l1,a.len()+b.l1);
c.r0=b.r0;
if (b.sum==0) c.r0=max(c.r0,b.len()+a.r0);
c.r1=b.r1;
if (b.sum==b.len()) c.r1=max(c.r1,b.len()+a.r1);
c.m0=max(max(a.m0,b.m0),a.r0+b.l0);
c.m1=max(max(a.m1,b.m1),a.r1+b.l1);
c.sum=a.sum+b.sum;
return c;
}
inline void pushup(int i){
int temp1=tree[i].rev,temp2=tree[i].tag;
tree[i]=tree[lc]+tree[rc];
tree[i].rev=temp1,tree[i].tag=temp2;
}
void Build(int i,int l,int r){
tree[i].l=l,tree[i].r=r;
tree[i].tag=-1;
if (l==r){
Cover(i,a[l]);
return ;
}
int mid=(l+r)>>1;
Build(lc,l,mid);
Build(rc,mid+1,r);
pushup(i);
}
void Update(int i,int L,int R,int val){
if (L<=tree[i].l&&tree[i].r<=R){
Cover(i,val);
return ;
}
int mid=(tree[i].l+tree[i].r)>>1;
pushdown(i);
if (L<=mid) Update(lc,L,R,val);
if (mid<R) Update(rc,L,R,val);
pushup(i);
}
void Reverse(int i,int L,int R){
if (L<=tree[i].l&&tree[i].r<=R){
Rev(i);
return ;
}
int mid=(tree[i].l+tree[i].r)>>1;
pushdown(i);
if (L<=mid) Reverse(lc,L,R);
if (mid<R) Reverse(rc,L,R);
pushup(i);
}
int QuerySum(int i,int L,int R){
if (L<=tree[i].l&&tree[i].r<=R){
return tree[i].sum;
}
int mid=(tree[i].l+tree[i].r)>>1,ans=0;
pushdown(i);
if (L<=mid) ans+=QuerySum(lc,L,R);
if (mid<R) ans+=QuerySum(rc,L,R);
return ans;
}
node QueryMax(int i,int L,int R){
if (L<=tree[i].l&&tree[i].r<=R){
return tree[i];
}
int mid=(tree[i].l+tree[i].r)>>1;
pushdown(i);
if (mid>=R) return QueryMax(lc,L,R);
else if (L>mid) return QueryMax(rc,L,R);
else return QueryMax(lc,L,R)+QueryMax(rc,L,R);
}
}
using namespace SegmentTree;
int main(){
int n=read(),m=read();
for (register int i=1;i<=n;++i){
a[i]=read();
}
Build(1,1,n);
while (m--){
int opr=read(),l=read()+1,r=read()+1;
if (opr==0) Update(1,l,r,0);
if (opr==1) Update(1,l,r,1);
if (opr==2) Reverse(1,l,r);
if (opr==3) printf("%d\n",QuerySum(1,l,r));
if (opr==4) printf("%d\n",QueryMax(1,l,r).m1);
}
}

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